50+25x=3x^2

Solution for 50+25x=3x^2 equation:

50+25x=3x^2

We move all terms to the left:

50+25x-(3x^2)=0

determiningTheFunctionDomain
-3x^2+25x+50=0

a = -3; b = 25; c = +50;
Δ = b2-4ac
Δ = 252-4·(-3)·50
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-35}{2*-3}=\frac{-60}{-6}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+35}{2*-3}=\frac{10}{-6}
=-1+2/3
$